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0=-58x-3x^2
We move all terms to the left:
0-(-58x-3x^2)=0
We add all the numbers together, and all the variables
-(-58x-3x^2)=0
We get rid of parentheses
3x^2+58x=0
a = 3; b = 58; c = 0;
Δ = b2-4ac
Δ = 582-4·3·0
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-58}{2*3}=\frac{-116}{6} =-19+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+58}{2*3}=\frac{0}{6} =0 $
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